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Tennispoll (halve) finale Kitzbuhel
#1
BEGIN
in Benneteau - Hernandez
in Garcia-Lopez - Youzhny

in Benneteau/Hernandez - Garcia-Lopez/Youzhny
END

BV1: Hoeveel breakpoints zijn er in de halve finales?
BV2: Hoeveel aces worden er geslagen in de halve finales?

Voorspellingen per PM naar mij sturen.
Ik heb mijn voorspellingen naar Elikian gestuurd.

Puntentelling:
Halve finale: 2+1
Finale: 3+1
Reply
#2
PM heeft geen nut hier, lijkt me.

BEGIN
2 in 2 Benneteau - Hernandez
2 in 2 Garcia-Lopez - Youzhny

2 in 2 Benneteau/Hernandez - Youzhny *
1 in 2 Benneteau/Hernandez - Garcia-Lopez*
END

BV1: Hoeveel breakpoints zijn er in de halve finales? 22
BV2: Hoeveel aces worden er geslagen in de halve finales? 19
Reply
#3
Mist (3) - Mitch (4)
2in2 - 2in3 Benneteau - Hernandez
2in2 - 1in3 Garcia-Lopez - Youzhny

Finale:
1in2 - 1in3 Benneteau - Garcia-Lopez
2in2 - 1in3 Hernandez - Youzhny

BV1: 22-18
Reply
#4
Alleen een toernooi-overwinning van Benneteau door Garcia-Lopez in de finale in 2 sets te verslaan en minimaal 15 breakpoints in de halve finale tegen Hernandez houden mij van de weekoverwinning af.
Dat dit ook zo gebeurt schat ik in op max. 5%.
Jammer dat er maar weinig punten te halen zijn.
Reply
#5
Wees nou maar gewoon blij dat die tie-break de goede kant op valt Wink
Reply
#6
Ik zie Benneteau wel in 2 sets van GGL winnen, maar die bp's zullen wel niet gehaald zijn.
In dat geval feli Mitch.
Reply
#7
Ik had het verkeerd gezien. Ik had sowieso al gewonnen.
Reply
#8
Gefeliciteerd.
Reply


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